2-SAT
Jul 18, 242-SAT
struct TwoSatSolver {
int n_vars;
int n_vertices;
vector<vector<int>> adj, adj_t;
vector<bool> used;
vector<int> order, comp;
vector<bool> assignment;
TwoSatSolver(int _n_vars) : n_vars(_n_vars), n_vertices(2 * n_vars), adj(n_vertices), adj_t(n_vertices), used(n_vertices), order(), comp(n_vertices, -1), assignment(n_vars) {
order.reserve(n_vertices);
}
void dfs1(int v) {
used[v] = true;
for (int u : adj[v]) {
if (!used[u])
dfs1(u);
}
order.push_back(v);
}
void dfs2(int v, int cl) {
comp[v] = cl;
for (int u : adj_t[v]) {
if (comp[u] == -1)
dfs2(u, cl);
}
}
bool solve_2SAT() {
order.clear();
used.assign(n_vertices, false);
for (int i = 0; i < n_vertices; ++i) {
if (!used[i])
dfs1(i);
}
comp.assign(n_vertices, -1);
for (int i = 0, j = 0; i < n_vertices; ++i) {
int v = order[n_vertices - i - 1];
if (comp[v] == -1)
dfs2(v, j++);
}
assignment.assign(n_vars, false);
for (int i = 0; i < n_vertices; i += 2) {
if (comp[i] == comp[i + 1])
return false;
assignment[i / 2] = comp[i] > comp[i + 1];
}
return true;
}
void add_disjunction(int a, bool na, int b, bool nb) {
// na and nb signify whether a and b are to be negated
a = 2 * a ^ na;
b = 2 * b ^ nb;
int neg_a = a ^ 1;
int neg_b = b ^ 1;
adj[neg_a].push_back(b);
adj[neg_b].push_back(a);
adj_t[b].push_back(neg_a);
adj_t[a].push_back(neg_b);
}
static void example_usage() {
TwoSatSolver solver(3); // a, b, c
solver.add_disjunction(0, false, 1, true); // a v not b
solver.add_disjunction(0, true, 1, true); // not a v not b
solver.add_disjunction(1, false, 2, false); // b v c
solver.add_disjunction(0, false, 0, false); // a v a
assert(solver.solve_2SAT() == true);
auto expected = vector<bool>(True, False, True);
assert(solver.assignment == expected);
}
};
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